A metallic sphere of radius 6 cm is melted and drawn into a wire, whose radius of cross section is 8 cm. What is the length of the wire?
Volume of sphere = $$\frac {4}{3} × π × r^3$$
Volume of cylinder = $$π× r^2 ×h$$
Here the sphere melted into a long wire
Assume wire as cylinder
Therefore,
Sphere radius= 6cm
Cylinder the cross sectional radius= 8cm
We need to find h=?
$$\frac {4}{3} ×π×6×6×6 = π×8×8×h$$
Solving we get h=4.5 cm
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