A die is thrown twice. What is the probability of getting a sum 7 from the two throws?
Number of ways in which the sum is 7 = (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) => 6 ways
Total number of possibilities = 6 * 6 = 36
Probability that sum is 7 = $$\frac{6}{36}$$ = $$\frac{1}{6}$$
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