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The length of a floor is 125% of its breadth. If the area of floor is $$125m^2$$, what is the sum of the length and the breadth of the floor? (in m)
Let breadth of floor = $$x$$ m
=> Length = $$\frac{125}{100}\times x=1.25x$$ m
Area = $$x\times1.25x=125$$
=> $$x^2=\frac{125}{1.25}=100$$
=> $$x=\sqrt{100}=10$$
$$\therefore$$ Sum of length and breadth = $$x+1.25x=2.25x$$
= $$2.25\times10=22.5$$Β
=> Ans - (B)
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