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Solution
$$\angle$$CPA = $$\angle$$DPB = 120° (Vertically opposite angles)
In $$\triangle$$ APC
=> $$\angle$$ ACP + $$\angle$$ CPA + $$\angle$$ PAC = $$180^{\circ}$$
=> $$\angle$$ PAC = $$180^{\circ} - 40^{\circ} - 120^{\circ} = 20^{\circ}$$
Also, $$\angle$$ PAC = $$\angle$$ PBD (Angles in the same segment)
=> $$\angle$$ PBD = $$y = 20^{\circ}$$
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