If $$\sin \theta$$ = 2/3, Find the value of $$\sec \theta$$ and $$\cot \theta$$.
$$\sin \theta =Â \frac{2}{3}$$
$$\sin\ =\frac{P}{H}$$ so, P = 2, H = 3 hence B =Â $$\sqrt{\ 5}$$
$$\sec \theta=\frac{H}{B\ }=\frac{3}{\sqrt{\ 5}}$$
$$\cot \theta=\frac{B}{P}=\frac{\sqrt{\ 5}}{2}$$
Create a FREE account and get: