Two real numbers $$a$$ and $$b$$, where $$a>b$$, are given such that their sum is equal to $$4$$ times their difference. The value of $$\frac{2ab}{3(a^2-b^2)}$$ is

A

$$\frac{2}{3}$$

B

$$\frac{1}{2}$$

C

1

D

$$\frac{5}{8}$$