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Consider the number of ways in which five girls and five boys sit in ten seats that are equally spaced around a circle. The proportion of the seating arrangements in which no two girls sit at the ends of a diameter is
Fix the circular seating structure and count the arrangements in which no pair of girls occupies opposite seats. The resulting proportion simplifies to $$\frac{5\cdot2\cdot5! \cdot5!}{10\cdot8!}=\frac{8}{63}$$. Hence the correct option is $$\frac{8}{63}$$.
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