If $$a = \sqrt[3]{4}, b = \sqrt[4]{5}, c = \sqrt[4]{7}$$ and $$d = \sqrt[3]{9}$$, then their correct ordering is

A

$$a < b < c < d$$

B

$$b < a < d < c$$

C

$$b < a < c < d$$

D

$$a < d < b < c$$