A train travelling with a speed of 60 km/hr catches another train travelling in the same direction and then leaves it 120 m behind in 18 seconds. The speed of the second train is
Speed of 2nd train be S m/sec
And 60 km/hr = $$ 60 \times \frac{5}{18} = \frac{50}{3} m/sec $$
As trains are traveling in same distance then,
Relative distance = $$ \frac{50}{3} - S = \frac{120}{18} $$
On solving, S = 10 m/sec
Speed of 2nd train = $$ 10 \times \frac{18}{5} = 36 km/hr $$
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