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Let the abscissae of the two points $$P$$ and $$Q$$ be the roots of $$2x^2 - rx + p = 0$$ and the ordinates of $$P$$ and $$Q$$ be the roots of $$x^2 - sx - q = 0$$. If the equation of the circle described on $$PQ$$ as diameter is $$2x^2 + y^2 - 11x - 14y - 22 = 0$$, then $$2r + s - 2q + p$$ is equal to ______.
Correct Answer: 7
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