Question 84

A Box contains three different types of old coins in the ratio 7:6:8, the values of old coins are 1 rupee, 5 rupees and 10 rupees respectively. If the total value of the coins in the box is Rs.936, find the number of old coins values 5 rupees.

Solution

Let number of 1 rupee, 5 rupees and 10 rupees respectively be $$7x,6x$$ and $$8x$$

Total amount = $$(1\times7x)+(5\times6x)+(10\times8x)=936$$

=> $$7x+30x+80x=936$$

=> $$x=\frac{936}{117}=8$$

$$\therefore$$ Number of 5 rupees coins = $$6\times8=48$$

=> Ans - (A)

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