The inner and outer circumference of a circular ring is 22 cm and 44 cm, respectively. What is the thickness of the ring?
The inner and outer circumference of a circular ring is 22 cm and 44 cm, respectively.
Let r1 and r2 be the inner and outer radius of the ring.
$$2\pi \times r1 = 22$$
$$ r1 = \frac{7}{2}$$
$$2\pi \times r2 = 44$$
$$r2 = 7$$
Thickness $$= r2-r1 = 7 - \frac{7}{2} = \frac{7}{2} = 3.5$$
OPtion C is correct.
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