If it is possible to form a number with the first, the fourth and the seventh digits of the number 4671358, which is the perfect square of a two-digit odd number, which of the following will be the digit in the tenth place of that two digit odd number ? If no such number can be formed, give 'O' as the answer and if more than one such number can be made, give 'X' as the answer.
Number - 4671358
1st, 4th and 7th digits = 4, 1, 8
Now, if a number should be a perfect square of an odd number, then the number should also be odd, i.e. end with '1' in this case.
Numbers ending with 1 = 481, 841
Now, $$841=(29)^2$$ and 481 is not a perfect square number.
Digit in 10th place = 2
=> Ans - (A)
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