If $$\dfrac{d}{dx}G(x) = \dfrac{e^{\tan x}}{x}$$, $$x \in (0, \pi/2)$$, then $$\int_{1/4}^{1/2} \dfrac{2}{x} \cdot e^{\tan(\pi x^2)} dx$$ is equal to

A

$$G(\pi/4) - G(\pi/16)$$

B

$$2[G(\pi/4) - G(\pi/16)]$$

C

$$\pi[G(1/2) - G(1/4)]$$

D

$$G(1/\sqrt{2}) - G(1/2)$$