Question 82

A committee of 3 members is to be selected out of 3 men and 2 women What is the probability that the committee has at least one woman ?

Solution

The number of ways = Two men and one woman + One man and two women 
                  = $$\frac{3C2 * 2C1}{5C3} + \frac{3C1 * 2C2}{5C3}$$

                              = $$\frac{6+3}{20}$$

                              = 9/10

Hence, the correct option is C.


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