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Question 82
A committee of 3 members is to be selected out of 3 men and 2 women What is the probability that the committee has at least one woman ?
Solution
The number of ways = Two men and one woman + One man and two women
= $$\frac{3C2 * 2C1}{5C3} + \frac{3C1 * 2C2}{5C3}$$
= $$\frac{6+3}{20}$$
= 9/10
Hence, the correct option is C.
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