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Two persons are walking in the same direction at rates 3 km/hr and 6 km/hr. A train comes running from behind and passes them in 9 and 10 seconds. The speed of the train is
Let the speed of train = S km/hr
Let the length of train = x meters
When a train crosses a man, it travels its own distance.
According to question,
Distance = Speed$$ \times $$Time
x = (S - 3)$$ \times \frac{5}{18} \times 9$$ (1)
Also,
x = (S - 6)$$ \times \frac{5}{18} \times 10$$ (2)
From equation (1) and (2)
(S - 3)$$ \times \frac{5}{18} \times 9$$ = (S - 6)$$ \times \frac{5}{18} \times 10$$
(S - 3)$$ \times $$9 = (S - 6)$$ \times $$10
9S - 27 = 10S - 60
10S - 9S = 60 - 27
S = 33 km/hr
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