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The value of $$2^{\log_6 18} \cdot 3^{\log_6 3}$$ in decimal form is _______
Correct Answer: 6
$$\log_6 18 = \log_6 (6 \times 3) = 1 + \log_6 3$$. So the expression is $$2 \cdot 2^{\log_6 3} \cdot 3^{\log_6 3} = 2 \cdot 6^{\log_6 3} = 2 \times 3 = 6$$.
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