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The solution set of the equation $$\sqrt{x^2 - 4x + 4} + (x - 2) = 0$$ is _______
Correct Answer: 0
PLACEHOLDER ANSWER - the answer is an interval. $$\sqrt{x^2 - 4x + 4} = \sqrt{(x - 2)^2} = |x - 2|$$, so the equation is $$|x - 2| = -(x - 2)$$. This holds exactly when $$x - 2 \le 0$$, so the solution set is $$(-\infty, 2]$$.
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