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Question 8

The graph between two temperature scales P and Q is shown in the figure. Between upper fixed point and lower fixed point there are 150 equal divisions of scale P and 100 divisions on scale Q. The relationship for conversion between the two scales is given by: 

image

Use the general relation for any linear temperature scales:

$$\frac{\text{Reading}-\text{Lower fixed point}}{\text{Upper fixed point}-\text{Lower fixed point}}=\text{constant}$$

For scale P:

  • Lower fixed point = 30
  • Upper fixed point = 180

For scale Q:

  • Lower fixed point = 0
  • Upper fixed point = 100

So,

$$\frac{t_P-30}{180-30}=\frac{t_Q-0}{100-0}$$

$$\frac{t_P-30}{150}=\frac{t_Q}{100}$$

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