Match List I with List II:
A. Isothermal Process   I. Work done by the gas decreases internal energy
B. Adiabatic Process   II. No change in internal energy
C. Isochoric Process   III. The heat absorbed goes partly to increase internal energy and partly to do work
D. Isobaric Process   IV. No work is done on or by the gas
Choose the correct answer from the options below:

Matching thermodynamic processes with their characteristics:

A. Isothermal Process: Temperature is constant, so internal energy doesn't change (for ideal gas). ΔU = 0, Q = W → II. No change in internal energy

B. Adiabatic Process: No heat exchange (Q = 0), so W = -ΔU. Work done by gas decreases internal energy → I. Work done by the gas decreases internal energy

C. Isochoric Process: Constant volume, so no work done (W = 0). All heat goes to change internal energy → IV. No work is done on or by the gas

D. Isobaric Process: Constant pressure, heat absorbed goes partly to increase internal energy and partly to do work (Q = ΔU + W) → III

Matching: A-II, B-I, C-IV, D-III

The correct answer is Option 2.