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In a parallelogram $$ABCD$$ if the lengths of two adjacent sides are 2, 6 and the length of the smallest diagonal $$BD$$ is 6 then $$AC^2 =$$ ______
Correct Answer: 44
In a parallelogram the sum of the squares of the diagonals equals the sum of the squares of the four sides, $$AC^2 + BD^2 = 2(2^2 + 6^2) = 80$$. With $$BD = 6$$, $$AC^2 = 80 - 36 = 44$$.
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