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2 × tan 30° / $$(1 + tan^2 30°)$$ equals:
sin 60°
cos 60°
tan 60°
sin 30°
$$\dfrac{2\times tan 30^\circ}{1+tan^2 30^\circ}$$$$= \dfrac{2\times\dfrac{1}{\sqrt{3}}}{1+(\dfrac{1}{\sqrt{3}})^2}$$$$= \dfrac{\dfrac{2}{\sqrt{3}}}{\dfrac{4}{3}}$$$$= \dfrac{2}{\sqrt{3}} \times \dfrac{3}{4}$$$$ = \dfrac{3}{2\sqrt{3}} = \dfrac{\sqrt{3}}{2} = sin 60^\circ$$
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