Let $$f(x) = x|x|$$ and $$g(x) = \sin x$$. Statement-1 : $$g \circ f$$ is differentiable at $$x = 0$$ and its derivative is continuous at that point. Statement-2 : $$g \circ f$$ is twice differentiable at $$x = 0$$.

A

Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1

B

Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1

C

Statement-1 is true, Statement-2 is false

D

Statement-1 is false, Statement-2 is true