Question 79

If $$\ 2^{3}\ $$# $$4^{3}\ $$ @$$\ 3^{3}\ $$= 45 and $$\ 3^{3}\ $$# $$\ 5^{3}\ $$@ $$\ 4^{3}\ $$= 88, then $$\ 4^{3}\ $$# $$\ 2^{3}\ $$@ $$\ 1^{3}\ $$= ?

Solution

If we replace # with '+' and @ with '-', then we get the desired result.

Eg :- $$[(2)^3+(4)^3]-(3)^3=(8+64-27)=45$$

and $$[(3)^3+(5)^3]-(4)^3=(27+125-64)=88$$

Similarly, $$[(4)^3+(2)^3]-(1)^3=(8+64-1)=71$$

=> Ans - (B)

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