MAT 2003 Question Paper

Question 78

Two trains of equal length are running on parallel lines in the same direction at 46 km and 36 km per hr. The faster train passes the slower train in 36 sec. The length of eachtrain is

Solution

Let length of each train = $$x$$ m

Relative speed = $$(46-36)\times\frac{5}{18}=\frac{50}{18}$$ m/s

=> $$\frac{x+x}{\frac{50}{18}}=36$$

=> $$\frac{36x}{50}=36$$

=> $$x=50$$ m

=> Ans - (A)


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