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Question 78
Two trains of equal length are running on parallel lines in the same direction at 46 km and 36 km per hr. The faster train passes the slower train in 36 sec. The length of eachtrain is
Solution
Let length of each train = $$x$$ m
Relative speed = $$(46-36)\times\frac{5}{18}=\frac{50}{18}$$ m/s
=> $$\frac{x+x}{\frac{50}{18}}=36$$
=> $$\frac{36x}{50}=36$$
=> $$x=50$$ m
=> Ans - (A)
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