If $$f'(x) = \sin(\log x)$$ and $$y = f\left(\dfrac{2x+3}{3-2x}\right)$$, then $$\dfrac{dy}{dx}$$ equals

A

$$\sin\left[\log\left(\dfrac{2x+3}{3-2x}\right)\right]$$

B

$$\dfrac{12}{(3-2x^2)}$$

C

$$\dfrac{12}{(3-2x)^2}\sin\left[\log\left(\dfrac{2x+3}{3-2x}\right)\right]$$

D

$$\dfrac{12}{(3-2x)^2}\cos\left[\log\left(\dfrac{2x+3}{3-2x}\right)\right]$$