Question 76

$$x^{y}=y^{x}\Rightarrow \left(\frac{x}{y}\right)^{\frac{y}{x}} =$$

given thatΒ 

Β $$x^{y}=y^{x}$$

so we can write that $$y = x^\frac{y}{x}$$Β 

and substituting the value to

$$x^\frac{y}{x}$$

we get $$\frac{x}{x^\frac{y}{x}^\frac{x}{y} $$

= {x^$$\frac{x}{y}$$Β  $$frac {x^1}$$

x^$$\frac{x}{y}-1$$ answerΒ 

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