Solution
given that
$$x^{y}=y^{x}$$
so we can write that $$y = x^\frac{y}{x}$$
and substituting the value to
$$x^\frac{y}{x}$$
we get $$\frac{x}{x^\frac{y}{x}^\frac{x}{y} $$
= {x^$$\frac{x}{y}$$ $$frac {x^1}$$
x^$$\frac{x}{y}-1$$ answer
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