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Instructions: Study the given information carefully to answer the questions that follows.
An urn contains 4 green, 5 blue, 2 red and 3 yellow marbles.
Question 76
If two marbles are drawn at random, what is the probability that both are red or at least one is red?
Solution
Out of two red marbles two can be choosen in 2C2 ways
Out of two red marbles one can be choosen in 2C1 ways
Sum of blue, yellow and green marbles = 12
Out of 12 marbles one can be choosen in 12C1 ways
The probability that both are red or atleast one is red = [2C2 + (2C1 x 12C1)]/14C2 = $$\frac{25}{91}$$
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