Numbers between 1 to 200 which are divisible by 3 = 3,6,9,.........,198
This is an AP with first term $$a=3$$ and common difference $$d=3$$
Last term of AP = $$a+(n-1)d$$
=> $$3+(n-1)3=198$$
=> $$(n-1)3=198-3=195$$
=> $$(n-1)=\frac{195}{3}=65$$
=> $$n=65+1=66$$
Now, numbers which are divisible by L.C.M.(3,7) = 21 are : 21,42,63,......,189
Similarly, $$21+(n-1)21=189$$
=> $$(n-1)21=189-21=168$$
=> $$(n-1)=\frac{168}{21}=8$$
=> $$n=8+1=9$$
$$\therefore$$ Numbers between 1 to 200 which are divisible by 3 but not by 7 = $$66-9=57$$
=> Ans - (C)
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