Given that $$\wedge_m^\alpha = 133.4 (AgNO_3); \wedge_m^\alpha = 149.9(KCl); \wedge_m^\alpha = 144.9S cm^2 mol^{-1} (KNO_3)$$ the molar conductivity at infinite dilution for AgCl is

A

$$132 S cm^2 mol^{-1}$$

B

$$140 S cm^2 mol^{-1}$$

C

$$138 S cm^2 mol^{-1}$$

D

$$134 S cm^2 mol^{-1}$$