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A solid sphere of radius $$r$$ is melted and with that material a solid cone and twenty two identical solid cubes were made. If the height of cone and edge of each cube are each equal 9 to half the radius of the sphere, then the ratio of the radius of the cone to its height is
Volume of the sphere is
$$=(4/3)Οr^3.$$
height of cone r/2.
let say radius of cone is a.
So, volume of cone isΒ
$$=(1/6)Οa^2r.$$
side of cube is $$=r/2.$$
volume of cube$$=r^3/8.$$
So,$$(4/3)Οr^3=(1/3)Οa^2r+r^3/8.$$
So,$$a=(β11/2)r$$.
So, height: radius$$=β11:1$$.
B is correct choice.
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