A 270 m long train running at a speed of 120 km/h crosses another train running in opposite direction at the speed of 80 km/h in 9 seconds. What is the length of the other train?
let first train be a and second train be b
length of a = 270 m
speed of a= 120 km/hr = $$120\times{\frac{5}{18}}$$ = $$\frac{100}{3}$$ m/sec
speed of b = 80 km/hr =Â Â $$80\times{\frac{5}{18}}$$ = $$\frac{200}{9}$$ m/sec
average speed =Â Â $$\frac{100}{3}$$ +Â $$\frac{200}{9}$$Â = $$\frac{500}{9}$$
$$\frac{270 + x}{\frac{500}{9}Â }$$ =Â 9
270 + x = $$9\times\frac{500}{9}$$
x = 500 - 270
x = 230 m
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