Question 75

Two successive discounts, the first being $$14\frac{1}{2}$$% were given on an article having a marked price of ₹12,500. Finally, it was sold for ₹9,405. How much was the second discount?

Solution

Let's assume the second discount was 'y'%.

Two successive discounts, the first being $$14\frac{1}{2}$$% were given on an article having a marked price of ₹12,500. Finally, it was sold for ₹9,405.

12500 of (100-14.5)% of (100-y)% = 9405

12500 of 85.5% of (100-y)% = 9405

$$12500\times\frac{85.5}{100}\times\ \frac{(100-y)}{100}=9405$$

$$\frac{10687.5}{100}\times\ (100-y)=9405$$

$$106.875\times\ (100-y)=9405$$

$$(100-y) = 88$$

y = 100-88

= 12

So second discount = y = 12%


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