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The solution of $$x\frac{dy}{dx} + y = x^{4}$$ with the condition $$y(1) = \frac{6}{5}$$ is:
y=$$\frac{x^{4}}{5}+\frac{1}{x}$$
y=$$\frac{4x^{4}}{5}+\frac{4}{5x}$$
y=$$\frac{x^{4}}{5}+1$$
y=$$\frac{x^{4}}{5}+4$$
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