The solution of $$x\frac{dy}{dx} + y = x^{4}$$ with the condition $$y(1) = \frac{6}{5}$$ is:

A

y=$$\frac{x^{4}}{5}+\frac{1}{x}$$

B

y=$$\frac{4x^{4}}{5}+\frac{4}{5x}$$

C

y=$$\frac{x^{4}}{5}+1$$

D

y=$$\frac{x^{4}}{5}+4$$