A man walks from point X to Y at a speed of 20 km/h, but comes back from point Y to X at a speed of 25 km/h. Find his average speed.
Let the distance between point X and Y = d
Speed of the man from point X to Y = 20 km/h
Time taken by the man from point X to Y =Â $$\frac{d}{20}$$
Speed of the man from point Y to X = 25 km/h
Time taken by the man from point Y to X = $$\frac{d}{25}$$
$$\therefore\ $$Average Speed = $$\frac{\text{Total Distance travelled}}{\text{Total time taken}}$$
= $$\frac{d+d}{\frac{d}{20}+\frac{d}{25}}$$
= $$\frac{2d}{\frac{9d}{100}}$$
= $$\frac{200}{9}$$
= $$22\frac{2}{9}$$ km/h
Hence, the correct answer is Option A
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