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A cylinder of height 4 cm and base radius 3 cm is melted to form a sphere. The radius of sphere is:
3 cm
3.5 cm
4 cm
2.5 cm
In both the cases volume remains the sameTherefore $$\frac{4}{3}\pi r^{3}$$=$$\pi R^{2}h$$$$r^{3}$$=27r=3 cm
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