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Question 75
A ball of 0.1 kg is dropped from rest. When it falls through a distance of 2 m, the work done by the force of gravity is (g = 9.8 m/s$$^2$$):
Solution
Work done by the gravity = mgh
=$$0.1\times 9.8\times 2$$
=$$0.2\times 9.8$$
=1.96J
Work done by the gravity in this case will be positive as acceleration due to gravity is acting in the same direction of the ball.
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