Question 73
The product of two numbers is 2160 and their HCF is 12. Numbers of such possible pairs is
Solution
H.C.F. of the two numbers is 12, let the numbers be $$12x$$ and $$12y$$, where $$x$$ and $$y$$ are co-prime
Product = $$(12x)\times(12y)=2160$$
= $$xy=\frac{2160}{144}$$
=> $$xy=15$$
Now, factors of 15 = 1, 3, 5, 15
Thus, possible values of $$(x,y)=(1,15),(3,5)$$
$$\therefore$$ 2 such pairs are possible.
=> Ans - (B)
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