The product of two numbers is 2160 and their HCF is 12. Numbers of such possible pairs is
H.C.F. of the two numbers is 12, let the numbers be $$12x$$ and $$12y$$, where $$x$$ and $$y$$ are co-prime
Product = $$(12x)\times(12y)=2160$$
=Â $$xy=\frac{2160}{144}$$
=> $$xy=15$$
Now, factors of 15 = 1, 3, 5, 15
Thus, possible values of $$(x,y)=(1,15),(3,5)$$
$$\therefore$$ 2 such pairs are possible.
=> Ans - (B)
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