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$$\int_0^{\infty} \frac{6}{e^{3x} + 6e^{2x} + 11e^x + 6} dx =$$
$$\log_e\left(\frac{32}{27}\right)$$
$$\log_e\left(\frac{512}{81}\right)$$
$$\log_e\left(\frac{256}{81}\right)$$
$$\log_e\left(\frac{302}{27}\right)$$
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