The general solution of the differential equation $$9yy'+4x = 0$$ is, $$( y' = \frac{dy}{dx}$$, C= constant ) 

A

$$9x^{2}+4y^{2}$$=C

B

$$\frac{x^{2}}{9}+\frac{y^{2}}{4}=C$$

C

$$4x^{2}+9y^{2}$$=C

D

$$\frac{x^{2}}{4}-\frac{y^{2}}{9}=C$$