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The general solution of the differential equation $$9yy'+4x = 0$$ is, $$( y' = \frac{dy}{dx}$$, C= constant )ย
$$9x^{2}+4y^{2}$$=C
$$\frac{x^{2}}{9}+\frac{y^{2}}{4}=C$$
$$4x^{2}+9y^{2}$$=C
$$\frac{x^{2}}{4}-\frac{y^{2}}{9}=C$$
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