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The first electron gain enthalpies of $$F$$, $$Cl$$, $$Br$$ and $$I$$ are given below in a random order:
$$-295,\quad -328,\quad -349,\quad -325;kJ,mol^{-1}$$
Identify and enter the numerical value of the magnitude of electron gain enthalpy of $$Br$$ in $$kJ,mol^{-1}$$.
Correct Answer: -325
1. Establish the Halogen Trend
a) The correct decreasing order of negative electron gain enthalpy for halogens is
$$\mathrm{Cl>F>Br>I}$$
b) Fluorine has a slightly lower negative value than chlorine due to significant inter-electronic repulsions in its compact
$$2p$$ subshell.
2. Match Values to Elements
a) $$\mathrm{Cl=-349\ kJ\,mol^{-1}}$$
b) $$\mathrm{F=-328\ kJ\,mol^{-1}}$$
c) $$\mathrm{Br=-325\ kJ\,mol^{-1}}$$
d) $$\mathrm{I=-295\ kJ\,mol^{-1}}$$
3. Extract the Magnitude
a) The electron gain enthalpy value for bromine is
$$-325\ \mathrm{kJ\,mol^{-1}}$$
b) Taking the absolute magnitude gives a final positive value of
$$ Correct answer: -{325\ \mathrm{kJ\,mol^{-1}}}$$
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