Question 72

Find the value of $$ 1^2 + 2^2 + 3^2+ ...... + 10^2 $$

Solution

sum of squares of first n natural numbers = $$ \frac{ n(n + 1)(2n + 1)}{6} $$

here n = 10

$$ \frac{10 ( 10 + 1)( 20 + 1)}{6} = \frac{ 10 \times 11 \times 21}{6} $$

= 385

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