A spherical glass vessel has a cylindrical neck 7 cm long and 4 cm in diameter. The diameter of the spherical part is 21 cm. Find the quantity of water it can hold.
Diameter of spherical part =21cm
D=2r;
Radius(r)$$=\frac{21}{2} =10.5cm$$
Diameter of cylindrical part =4cm
Radius(r)$$=\frac{4}{2} =2cm$$
Volume of the spherical part =$$ \frac{4}{3}πr^3$$
$$ \frac{4}{3}\times\frac{22}{7}\times(10.5)^3$$
= 4851 cm
Volume of cylinder part =$$πr^2h$$
$$\frac{22}{7}\times2\times2\times7$$
= $$88 cm^3$$
Quantity of the water that vessel can hold= 88+4851
=$$4939 cm^3$$
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