A bullet is fired vertically upwards with a velocity of 196 m/sec. What is the maximum height reached by the bullet ? (Assuming g-9.8 miser-2)
u = initial velocity = 196 m/s
v = final velocity = 0 m/s
As it reaches highest point, velocity of bullet becomes zero.
g = acceleration due to gravity = 9.8 m/$$s*2$$
h = Maximum Height
$$v^2 - u^2 = 2gh$$
$$0 -Â 196^2 = 2 \times 9.8 \times h$$
h =Â 1960Â
So, the answer would be option a)1960 m
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