A dairyman pays Rs. 6.4 per liter of milk. He adds water and sells the mixture at Rs. 8 per liter, thereby making 37.5% profit. The proportion of water to milk received by the customers is
Let quantity of milk purchased be $$x$$ litres and water added be $$y$$ litres
Thus, cost price = Rs. $$6.4x$$
Selling price = Rs.ย $$8(x+y)$$
Also, profit % = 37.5 % = $$\frac{3}{8}$$
=> $$\frac{8(x+y)-6.4x}{6.4x}=\frac{3}{8}$$
=> $$1.6x+8y=2.4x$$
=> $$8y=0.8x$$
=> $$\frac{y}{x}=\frac{1}{10}$$
=> Ans - (B)
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