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The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality (in $$\text{mol kg}^{-1}$$) of the aqueous solution is
Take 1 mol of solution in total, with 0.8 mol of water and 0.2 mol of solute. The water weighs $$0.8 \times 18 = 14.4\text{ g} = 0.0144\text{ kg}$$. So the molality is $$\frac{0.2}{0.0144} \approx 13.88\text{ mol kg}^{-1}$$.
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