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Find the value $$sin75^\circ$$?
$$\frac{\sqrt{6}-\sqrt{2}}{4}$$
$$\frac{\sqrt{6}+\sqrt{2}}{4}$$
$$\frac{\sqrt{3}+1}{2}$$
$$\frac{\sqrt{3}-1}{2\sqrt{2}}$$
sin(A+B) ≡ sin(A)cos(B) + sin(B)cos(A)
⇒ sin(75°) = sin(30+45)° = sin(30°)cos(45°) + sin(45°)cos(30°)
= ½ × 1/√2 + 1/√2 ×(√3)/2 = 1/(2√2) + (√3)/(2√2)
= (1+√3)/(2√2)
=(√2+√6)/4.B is correct choice.
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