Question 69
If the length of a rectangule is reduced by 10% and its breadth is increased by 10%, then the area
Solution
Let length and breadth of rectangle initially be 10 cm each
Area = $$A=lb=10\times10=100$$ $$cm^2$$
New length after 10% decrease = 9 cm and similarly new breadth = 11 cm
=> New area = $$A'=9\times11=99$$ $$cm^2$$
$$\therefore$$ Decrease in area = $$\frac{100-99}{100}\times100=1\%$$
=> Ans - (B)
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