Question 69

If the length of a rectangule is reduced by 10% and its breadth is increased by 10%, then the area

Solution

Let length and breadth of rectangle initially be 10 cm each

Area = $$A=lb=10\times10=100$$ $$cm^2$$

New length after 10% decrease = 9 cm and similarly new breadth = 11 cm

=> New area = $$A'=9\times11=99$$ $$cm^2$$

$$\therefore$$ Decrease in area = $$\frac{100-99}{100}\times100=1\%$$

=> Ans - (B)

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