Question 68

Two numbers are such that their product, their sum and their difference are in the ratio 24 : 7 : 1. Then their product is

Name: Two numbers are such that their product, their sum and their difference are in the ratio 24 : 7 : 1. Then their product is
Uploaded: 2026-04-30T12:55:02.589516+05:30
Duration: 3 min 14 s
Description: Two numbers are such that their product, their sum and their difference are in the ratio 24 : 7 : 1. Then their product is

Solution

Let the numbers be $$a$$ and $$b$$

According to ques, => $$ab:(a+b):(a-b)=24:7:1$$

Thus, $$\frac{a+b}{a-b}=\frac{7}{1}$$

=> $$a+b=7a-7b$$

=> $$6a=8b$$

=> $$\frac{a}{b}=\frac{4}{3}$$

Let $$a=4y$$ and $$b=3y$$

Also, $$\frac{ab}{a-b}=\frac{24}{1}$$

=> $$\frac{4y\times3y}{4y-3y}=24$$

=> $$12y^2=24y$$

=> $$y=2$$

$$\therefore$$ Numbers are $$a=8$$ and $$b=6$$

=> Product = $$ab=8\times6=48$$

=> Ans - (B))

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