Question 67

The ratio of the area of two triangles is 2 : 3 and ratio of their height is 3 : 2. The ratio of their bases is:

Solution

Let height of the two triangles be 3 and 2 units respectively.

Let bases of the two triangles be $$b_1$$ and $$b_2$$ units respectively.

=> Ratio of area of triangles = $$\frac{\frac{1}{2}\times b_1\times h_1}{\frac{1}{2}\times b_2\times h_2}=\frac{2}{3}$$

=> $$\frac{3b_1}{2b_2}=\frac{2}{3}$$

=> $$\frac{b_1}{b_2}=\frac{4}{9}$$

$$\therefore$$ Required ratio = 4 : 9

=> Ans - (B)

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