Question 67
The ratio of the area of two triangles is 2 : 3 and ratio of their height is 3 : 2. The ratio of their bases is:
Solution
Let height of the two triangles be 3 and 2 units respectively.
Let bases of the two triangles be $$b_1$$ and $$b_2$$ units respectively.
=> Ratio of area of triangles = $$\frac{\frac{1}{2}\times b_1\times h_1}{\frac{1}{2}\times b_2\times h_2}=\frac{2}{3}$$
=> $$\frac{3b_1}{2b_2}=\frac{2}{3}$$
=> $$\frac{b_1}{b_2}=\frac{4}{9}$$
$$\therefore$$ Required ratio = 4 : 9
=> Ans - (B)
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